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How do you calculate ##Arccos (sin (pi/6))##?

    Find ##arccos(sin (pi/6))##

    Ans: ##+- pi/3##

    ##sin (pi/6) = 1/2## therefor ##arccos (sin(pi/6)) = arccos (1/2)## On the trig unit circle,

    ##cos x = 1/2## –> arc ##x = +- pi/3##

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