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How do you verify ##sinx/(1-cosx) + (1-cosx)/sinx = 2cscx##?

    ##sinx/(1-cosx)+(1-cosx)/sinx = 2cscx##

    ##sinx/(1-cosx)+(1-cosx)/sinx = [sin^2x+(1-cosx)^2]/[(1-cosx)sinx]##

    ## = [sin^2x+cos^2x+1-2cosx]/[(1-cosx)sinx]##

    ## = [1+1-2cosx]/[(1-cosx)sinx]##

    ## = [2-2cosx]/[(1-cosx)sinx]##

    ## = 2cancel[1-cosx]/[cancel(1-cosx)sinx]##

    ## = 2/sinx##

    ## = 2cscx##